The question was:
Hannah has 6 orange sweets and some yellow sweets.
Overall, she has n sweets. She takes one sweet from the bag and then another.
The probability of her taking 2 orange sweets is 1/3.
Prove that:
The question is not actually that difficult if you remember how tree diagrams work.
When Hannah first takes a sweet there are 6 orange sweets out of n, so the probability of her choosing orange is 6/n.
When she chooses her second sweet there are now only 5 orange (if she chose orange the first time) out of a total of n-1 sweets.
You multiply the probabilities along the branches of a tree diagram, so
Multiplying the 2 fractions on the left gives:
